A change of 0.10 inHg corresponds to how many feet of altitude change?

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Test your knowledge of pitot-static systems for aviation exams. Study with multiple-choice questions and detailed explanations. Prepare effectively for success on your exam!

Multiple Choice

A change of 0.10 inHg corresponds to how many feet of altitude change?

Explanation:
A small change in ambient pressure translates into a proportional altitude change using the standard atmosphere: about 1 inch of mercury corresponds to roughly 1,000 feet near sea level. Therefore, a change of 0.10 inHg is about 0.10 × 1,000 = 100 feet. This is why a 0.10 inHg difference corresponds to an approximate 100 ft altitude change. The other options would require correspondingly smaller or larger pressure changes (for example, 1,000 ft would be about 1 inHg, and 10–20 ft would be about 0.01–0.02 inHg).

A small change in ambient pressure translates into a proportional altitude change using the standard atmosphere: about 1 inch of mercury corresponds to roughly 1,000 feet near sea level. Therefore, a change of 0.10 inHg is about 0.10 × 1,000 = 100 feet. This is why a 0.10 inHg difference corresponds to an approximate 100 ft altitude change. The other options would require correspondingly smaller or larger pressure changes (for example, 1,000 ft would be about 1 inHg, and 10–20 ft would be about 0.01–0.02 inHg).

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